Sure, I'd be happy to help you with that advanced math problem!
To find the limit of y = x ln(1 + 1/x) as x tends to 0 and positive infinity, we need to apply the appropriate limit laws and algebraic manipulations.

Limit as x tends to 0:
Let's first simplify the expression by applying the rule: lim(x→0) x ln(1 + 1/x) = lim(x→0) ln(1 + 1/x) / (1/x)
Now, we can use the limit laws and algebraic manipulations:
lim(x→0) ln(1 + 1/x) / (1/x) = lim(x→0) [ln(1 + 1/x)] / [(1/x)]
= lim(x→0) [ln(x + 1) - ln(x)] / [(x + 1 - x)/x]
= lim(x→0) [ln(x + 1) - ln(x)] / [1/x]
= lim(x→0) [(d/dx) ln(x)] (Using L'Hospital's rule)
= lim(x→0) 1/x
= ∞
Limit as x tends to positive infinity:
lim(x→∞) x ln(1 + 1/x) = lim(x→∞) ln(1 + 1/x) / (1/x)
= lim(x→∞) [ln(x + 1) - ln(x)] / [(x + 1 - x)/x]
= lim(x→∞) [ln(x + 1) - ln(x)] / [1/x]
= lim(x→∞) [(d/dx) ln(x)] (Using L'Hospital's rule)
= lim(x→∞) 1/x
= 0

Therefore, the limit of y = x ln(1 + 1/x) as x tends to 0 is positive infinity (∞), and the limit as x tends to positive infinity is 0.

Claude Sonnet

索尼、摩托罗拉、Zenfone 、谷歌，一加已经是 colorOS 了，

有消息了吗？

@tcpdump +1 ，我的也是，你的是美国手机号吗？

靠近香港去香港，离香港太远去某宝

外卖、快递、导航

恭喜

也有可能检测到不是美国 IP

我也是这样的，会不会必须要谷歌手机才可以？

普通人价值就是吃好、玩好。对自己亲人尽到责任就行了

Gemini Ultra 不是要推出了吗，可以期待一下，这个才是对标 GPY-4

我感觉这个 AI 嘘头大于实际，没有太大实用性

这个浏览器只有 ios 版本吗？ PC 、Android 没有吗？

全面屏确实牛逼

应该是有规则的，你可能触发了规则，

@Goooooos 真的吗老哥？

nothing 2 也可以，也是类原生系统