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This topic created in 1871 days ago, the information mentioned may be changed or developed.
代码如下：
import _thread as thread
stdoutmutex = thread.allocate_lock()
exitmutexes = [thread.allocate_lock() for i in range(10)]
def counter(myId, count):
for i in range(count):
print('1 %s -> %s' % (myId, stdoutmutex.locked()))
stdoutmutex.acquire()
print('2 %s -> %s' % (myId, stdoutmutex.locked()))
print(stdoutmutex.locked())
print('[%s] => %s' % (myId, i))
stdoutmutex.release()
exitmutexes[myId].acquire()
for i in range(10):
thread.start_new_thread(counter, (i, 10))
for mutex in exitmutexes:
while not mutex.locked(): pass
print('Main thread exiting')
问题： exitmutexes[myId].acquire()获得了锁的状态，while not mutex.locked(): pass 判断没有锁的话就继续执行，但我不知道什么时候释放的锁。 谢谢大家了！
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1
linw1995 Mar 18, 2021
想感知线程中函数的执行情况，可以用 Thread.join 。或者更细粒度的可以用 threading.Event
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2
no1xsyzy Mar 18, 2021
while not mutex.locked(): pass
这是判断没有锁就卡住，有锁继续执行。 |
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3
shenyansycn OP @no1xsyzy 应该是有锁就卡住，没锁才执行 pass 吧
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4
shenyansycn OP @no1xsyzy 我明白了，谢谢！
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