代码如下:
import _thread as thread
stdoutmutex = thread.allocate_lock()
exitmutexes = [thread.allocate_lock() for i in range(10)]
def counter(myId, count):
for i in range(count):
print('1 %s -> %s' % (myId, stdoutmutex.locked()))
stdoutmutex.acquire()
print('2 %s -> %s' % (myId, stdoutmutex.locked()))
print(stdoutmutex.locked())
print('[%s] => %s' % (myId, i))
stdoutmutex.release()
exitmutexes[myId].acquire()
for i in range(10):
thread.start_new_thread(counter, (i, 10))
for mutex in exitmutexes:
while not mutex.locked(): pass
print('Main thread exiting')
问题: exitmutexes[myId].acquire()获得了锁的状态,while not mutex.locked(): pass 判断没有锁的话就继续执行,但我不知道什么时候释放的锁。 谢谢大家了!
1
linw1995 2021-03-18 11:31:06 +08:00
想感知线程中函数的执行情况,可以用 Thread.join 。或者更细粒度的可以用 threading.Event
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2
no1xsyzy 2021-03-18 13:20:21 +08:00
while not mutex.locked(): pass
这是判断没有锁就卡住,有锁继续执行。 |
3
shenyansycn OP @no1xsyzy 应该是有锁就卡住,没锁才执行 pass 吧
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4
shenyansycn OP @no1xsyzy 我明白了,谢谢!
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