字典合并问题请教

[huangmiao233]

有以下 4 个字典

dict1={'status':'on', 'location':'a'}
dict2={'status':'on', 'location':'b'}
dict3={'status':'off', 'location':'c'}
dict4={'status':'off', 'location':'d'}

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有没有什么办法快速得到

result = {'on':['a','b'], 'off':['c','d']}

[maichael]

把四个字典放在一个数组里，一次遍历判断就搞定了。

[j0hnj]

from collections import defaultdict

result = defaultdict(set)
for d in [dict1, dict2, dict3, dict4]:
result[d['status']].add(d['location'])
result = {k:list(v) for k,v in result.items()}

[huangmiao233]

明白了 ！！多谢 2 位

[cassidyhere]

from operator import itemgetter
from itertools import groupby

rows = [dict1, dict2, dict3, dict4]
for status, items in groupby(rows, key=itemgetter('status')):
print(status, [i['location'] for i in items])

[huangmiao233]

python 还是有很多模块能用的 还是太年轻

[xpresslink]

@helijia21 根本用不着模块啊，就一句的事儿。
dict1={'status':'on', 'location':'a'}
dict2={'status':'on', 'location':'b'}
dict3={'status':'off', 'location':'c'}
dict4={'status':'off', 'location':'d'}
dicts = [dict1,dict2,dict3,dict4]
result = {}
for d in dicts: result.setdefault(d['status'],[]).append(d['location'])
print(result)
# {'on': ['a', 'b'], 'off': ['c', 'd']}