运行下面的命令;
$ ll /usr/lib/libfastcommon.so
-rwxr-xr-x 1 root wheel 250604 11 27 21:35 /usr/lib/libfastcommon.so*
$ ll /usr/lib64/libfastcommon.so
-rwxr-xr-x 1 root wheel 250604 11 27 21:35 /usr/lib64/libfastcommon.so*
$ gcc -L/usr/lib64 -lfastcommon
Undefined symbols for architecture x86_64:
"_main", referenced from:
implicit entry/start for main executable
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
$ gcc -L/usr/lib -lfastcommon
ld: library not found for -lfastcommon
clang: error: linker command failed with exit code 1 (use -v to see invocation)
问题是,为什么明明存在 /usr/lib/libfastcommon.so 文件, gcc -L/usr/lib -lfastcommon 确报错??
环境:
$ uname -a
Darwin gfdeMacBook-Air.local 15.0.0 Darwin Kernel Version 15.0.0: Wed Aug 26 16:57:32 PDT 2015; root:xnu-3247.1.106~1/RELEASE_X86_64 x86_64
$ gcc -v
Configured with: --prefix=/Applications/Xcode.app/Contents/Developer/usr --with-gxx-include-dir=/Applications/Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX10.11.sdk/usr/include/c++/4.2.1
Apple LLVM version 7.0.0 (clang-700.1.76)
Target: x86_64-apple-darwin15.0.0
Thread model: posix
1
zts1993 2015-11-27 23:37:32 +08:00
so 是 32 位,, gcc 64 位默认找 64 位。。我也不太懂。。
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2
proudzhu 2015-11-28 08:22:37 +08:00 via Android
因为 /usr/lib 是个软链接?不是提示用 -v 查看错误的吗?
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3
nareix 2015-11-28 09:25:56 +08:00
能 diff 下 /usr/lib/libfastcommon.so /usr/lib64/libfastcommon.so 吗
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4
kiwi95 2015-11-28 12:34:06 +08:00
.so 在 /lib64 下做一个软连接试试,之前遇到过类似的问题
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5
palfortime 2015-11-28 12:42:22 +08:00 via Android
gcc -L/usr/lib64 -lfastcommon
这行命令的输出说了没有 main 入口, gcc 是要编出一个可执行的文件。 |